MotoGP » Qatar MotoGP: Ben Spies still one of the fastest - Lorenzo


“I believe he is one of the fastest riders in MotoGP” - Jorge Lorenzo.

Sort Comments: Oldest | Newest

spies story - Unregistered

April 04, 2013 5:37 PM

Why is there even talk of Cal on a factory by yet. He is good, but he hasn't beaten a teammate in his MotoGP career. Colin beat him by 39 points in 2011 then was sent to Suter. Dovisioso beat him by 67 points last year.

This year will be the first year he will beat a teammate or at least he had better. If Cal doesn't beat Bradley in his first year he shouldn't be here.

I think Cal has the talent to get there, but let the results come first.

ZenKai - Unregistered

April 04, 2013 7:31 PM

It's really sad that the meager number of competitive factory teams and the complete lack of competitive satellite teams in Motogp can kill the careers of good riders like Spies, Dovi and Hayden. Pretty much, if you aren't in the top 4 at the moment, you have little chance of being in the top 4. Maybe the guys at Tech 3 can change that a little but we'll see.

Page 3 of 3
« 1 2 3 

Join the conversation - Add your comment

Please login or register before adding your comments.

Although the administrators and moderators of this website will attempt to keep all objectionable comments off these pages, it is impossible for us to review all messages. All messages express the views of the poster, and neither Crash Media Group nor Crash.Net will be held responsible for the content of any message. We do not vouch for or warrant the accuracy, completeness or usefulness of any message, and are not responsible for the contents of any message. If you find a message objectionable, please contact us and inform us of the problem or use the [report] function next to the offending post. Any message that does not conform with the policy of this service can be edited or removed with immediate effect.

© 1999 - 2014 Crash Media Group

The total or partial reproduction of text, photographs or illustrations is not permitted in any form.